题目概述

输入字符串转成double数字

题目分析

  1. 字符串是否为空
  2. 字符串是否包含非数字
  3. 字符串是否包含正负号
  4. 是否超过double最大值

题目解答

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package com.code.note.test;

public class Solution {

public Double parseDouble(String n) {

int isNegative = 1;

String numStr = n.trim();
if (numStr == null) return 0D;
if (numStr.length() > 0 && numStr.charAt(0) == '-') {
isNegative = -1;
numStr = numStr.substring(1);
} else if (numStr.charAt(0) == '+') {
numStr = numStr.substring(1);
}

if (!numStr.contains(".")) {
return (double) getHighPosNum(n);
}

String[] arr = numStr.split("\\.");

double sumHigh = getHighPosNum(arr[0]);

double sumLow = getLowPosNum(arr[1]);

return isNegative * (sumLow + sumHigh);
}

private long getHighPosNum(String highStr1) {
long sumHigh = 0;
String highStr = highStr1;
char[] highChars = highStr.toCharArray();
int[] highIntNums = new int[highChars.length];

for (int i = 0; i < highIntNums.length; i++) {
sumHigh += Math.pow(10, highIntNums.length - 1 - i) * isDigit(highChars[i]);
}
return sumHigh;
}

private int isDigit(char highChar) {
if (!Character.isDigit(highChar)) {
throw new NumberFormatException("非法数字");
}
return (int) highChar - (int) '0';
}

private double getLowPosNum(String lowStr1) {
double sumLow = 0D;
String lowStr = lowStr1;
char[] lowChars = lowStr.toCharArray();
int[] lowIntNums = new int[lowChars.length];

for (int i = 0; i < lowIntNums.length; i++) {
sumLow += Math.pow(10, -1 * (i + 1)) * (isDigit(lowChars[i]));
}
return sumLow;
}

public static void main(String[] args) {

Solution s = new Solution();
double a = s.parseDouble("-1.456");
System.out.println(a);
}
}